Hello. There are already 3,000,000,000 such questions here.
But I do not see how to take and learn serialization / deserialization JSON, using GSON.

There is an answer from the view server:

`{" p_result ":" ok "}`

This is a JSON type object, not an array, not anything else.

I need to get this very “OK”.

Also, I have an example of a working code, receiving from an array of values:

user.java
Public Class User {
Private String P_ID;
Private String P_NAME;
Private String P_LAST_NAME;
Public String GetID () {
  RETURN P_ID;
}
Public Void Setid (String ID) {
  this.p_id = id;
}
Public String GetName () {
  RETURN P_NAME;
}
Public Void SetName (String Name) {
  This.p_name = Name;
}
Public String GetLastName () {
  RETURN P_LAST_NAME;
}
Public Void Setname (String Lastname) {
  this.p_last_name = lastname;
}
}

to it:

Public Class JSONWORKER {
Public Static List & LT; User & gt; JSONTOUSERLIST (String Json)
{
  GSON GSON = NEW GSON ();
  Type Listtype = New TypeToken & lt; List & lt; User & gt; & gt; () {} .gettype ();
  Return Gson.Fromjson (JSON, ListType);
}
}

and method:

public static list & lt; user & gt; getUserFromServer () Throws IoException, JSonexception {
  Final List & LT; NameValuePair & GT; namevaluepairlist = new arraylist & lt; namevaluepair & gt; ();
  namevaluepairlist.add ("Query", "SPR_Employee_get"));
  namevaluepairlist.add (new basicnamevaluepair ("p_guid", user_guid));
  Final String Resp = Exchttpget (URL, NameValuePairlist);
  Jsonobject jsonobject = new jsonobject (RESP);
  if (jsonobject.has ("p_result")) {
    if (jsonobject.getstring ("p_result"). Equalsignorecase ("OK"))
      RETURN JSONWORKER.JSONTOUSERLIST (jsonobject.getjsonarray ("p_item"). Tostring ());
  }
  Return New ArrayList & LT; User & gt; ();
}

And I can’t even do …

Answer 1, Authority 100%

string json = "{\" p_result \ ": \" ok \ "}";
Result Result = New GSON (). Fromjson (JSON, Result.Class);
Public Class Result {
  @SerializedName ("P_Result")
  Private String Status;
  Public String GetStatus () {
    Return Status;
  }
}

p.s. By the way, in documentation everything is described in very detailed, with a bunch of visual examples …

Answer 2

I do not know from the point of view of rationality, but this option is quite worker:
It is necessary, for example, deserialize this line:

{"photos": {"page": 1, "pages": 10, "perpage": 100, "Total": 1000, "Photo": [{"ID": "31692962564", "Owner": "38589282 @ N03", "SECRET": "69A4DA0D87", "Server": "596", "Farm": 1, "title": "WALL", "ISPUBLIC": 1, "ISFRIEND": 0, "ISFAMILY": 0, "URL_S": "HTTPS: \ / / Farm1.StaticFlickr.com \ / 596 \ / 31692962564_69a4da0d87_m .jpg "," height_s ":" 180 "," width_s ":" 240 "}, {ID": "31692962804", "Owner": "136025614 @ n02", "secret": "CC66D3581F", "Server ":" 731 "," Farm ": 1," Title ":" Completely Hiding Blogger Widgets From Certain Pages "," ISPUBLIC ": 1," ISFRIEND ": 0," ISFAMILY ": 0," URL_S ":" https : \ / / Farm1.StaticFlickr.com \ / 731 \ /31692962804_cc66d3581f_m.jpg "," Height_s ":" 167 "," width_s ":" 240 "}

and so on.

And you need to pull out only the fields ID , title , url_s.

Public Class GalleryItem {
 @SerializedName ("Title")
 Private String McAPTION;
 @SerializedName ("ID")
 Private String Mid;
 @SerializedName ("URL_S")
 Private String Murl;
}
Public Void deser () {
 List & lt; GalleryItem & gt; Items = New ArrayList & lt; & gt; ();
 String JSONSTRING = "" {"PHOTOS": {"Page": 1, "Pages": 10, "PERPAGE" and TD ... ";
 JSONOBJECT JSONBODY = NEW JSONOBJECT (JSONSTRING); 
JSONObject photosJsonObject = jsonBody.getJSONObject ("photos");
  JSONArray photoJsonArray = photosJsonObject.getJSONArray ("photo");
  Gson gson = new Gson ();
  Type collectionType = new TypeToken & lt; List & lt; GalleryItem & gt; & gt; () {}. GetType ();
  items = gson.fromJson (photoJsonArray.toString (), collectionType);
}