It is necessary to calculate the amount of elements of each line of the matrix V (4.5) or the amount
Positive elements of the columns of this matrix at the instructions of the user.
There is a code that creates a matrix of the specified bearer and displays it (but for some reason only from positive numbers). But I do not know how to count the items and how to do it by selecting a user. If it is not difficult for you, I will be very grateful for your help.

# include & lt; iostream & gt;
# INCLUDE & LT; CTIME & GT;
Using Namespace STD;
INT MAIN ()
{
  SETLOCALE (0, "");
  SRAND (Unsigned (Time (NULL));
  int n, m;
  COUT & LT; & LT; "Enter the size of the matrix:";
  CIN & GT; & GT; N & gt; & gt; M;
  int ** a = new int * [n];
  for (int i = 0; i & lt; n; i ++)
    A [i] = new int [M];
  for (int i = 0; i & lt; n; i ++)
    for (int j = 0; j & lt; m; j ++)
      A [i] [j] = ((rand ()% 20));
 COUT & LT; & LT; "Your Matrix:" & LT; & LT; Endl & lt; & lt; Endl;
 for (int i = 0; i & lt; n; i ++)
 {
   for (int j = 0; j & lt; m; j ++)
     COUT & LT; & LT; A [i] [j] & lt; & lt; "";
   COUT & LT; & LT; Endl;
 }
 COUT & LT; & LT; Endl;
    for (int i = 0; i & lt; n; i ++)
      delete [] a [i];
    delete [] a;
}

Answer 1

Positive numbers, these are numbers that are more “0”, add a condition to this code code:

if (a [i] [j] & gt; 0)
   {
     SUM + = 1;
   }

So in the SUM variable you will receive the number of positive elements