Home c++ Segment division method in half

Segment division method in half

Author

Date

Category

In a properly written program, the number of calculation features differs from the number of iterations of the method on 2. How to fix the program to work correctly?

# include & lt; stdio.h & gt;
#Include & lt; math.h & gt;
INT SIGN (DOUBLE X);
Double SHAQ (Double X);
Double My_Exp (Double X);
INT ROOT_HALF (Double A, Double B, Double (* F) (Double), Double EPS)
{
Double C; int chislo = 0, funci = 0;
if (Sign (F (A)) == SIGN (F (B))) {PrintF ("method is not applicable \ n"); Return 0;}
do.
{
C = (A + B) /2.0;
if (SIGN (F (C)) == 0) {FUNCI ++; Printf ("Root:% LF \ N", C); break;}
ELSE.
IF (Sign (F (a)) == Sign (F (C))) {PrintF ("root:% lf \ n", c); a = c; funci + = 2;}
ELSE.
{printf ("root:% lf \ n", c); b = c;}
Chislo ++;
}
while (fabs (b-a) & gt; = eps);
Printf ("Number of iterations:% d \ n The number of calculations of functions:% d \ n", Chislo, FUNCI);
Return 0;
}
INT SIGN (DOUBLE X) {
IF (X & GT; 0) Return 1;
ELSE.
IF (X & LT; 0) Return -1;
ELSE if (x == 0) Return 0;
Return 0;
}
INT MAIN (Void)
{
Double A, B, F (Double), EPS = 0.01;
Scanf ("% le% lf", & amp; a, & amp; b);
root_half (a, b, & amp; f, eps);
Return 0;
}
Double F (Double X)
{
Return x * x * x -2 * x * x + 3;
}

I would do this:

# include & lt; stdio.h & gt;
#Include & lt; math.h & gt;
INT FUNCI;
Double F (Double X)
{
++ FUNCI;
Return x * x * x -2 * x * x + 3;
}
Double Root_half (Double A, Double B, Double (* F) (Double), Double EPS)
{
Double C; int chislo = 1;
double Fa = F (a), fb = f (b);
if (FA * FB & GT; 0) {PrintF ("method is not applicable \ n"); Return 0; }
for (; Fabs (B-a) & gt; = eps; chislo ++)
{
C = (A + B) /2.0;
Double FC = F (C);
if (fc == 0)
{
PrintF ("Number of iterations:% d \ n", chislo);
Return C;
}
if (FC * FA & GT; 0) {a = c; } else {b = c; }
}
PrintF ("Number of iterations:% d \ n", chislo);
Return C;
}
INT MAIN (Void)
{
Double A, B;
Scanf ("% LF% LF", & amp; a, & amp; b);
printf ("root =% lf \ n", root_half (a, b, f, 1e-5));
PrintF ("Function calls:% d \ n", Funci);
}

Why spend time searching for the correct question and then entering your answer when you can find it in a second? That's what CompuTicket is all about! Here you'll find thousands of questions and answers from hundreds of computer languages.