Help translate the C++ code

var d1, d2, d3, k, n: integer;
begin
  writeln ('Enter the number n with which we will compare the sum of the digits of the number');
  readln (n);
  k: = 0;
  {d1 - left, d2 - middle, d3 - right digits of the number}
  for d1: = 1 to 9 do
    for d2: = 0 to 9 do
      for d3: = 0 to 9 do
        if (d1 + d2 + d3 = n) then
        begin
          k: = k + 1;
          write (d1, d2, d3, '');
        end;
  writeln ('The number of required numbers is -', k);
end.

Answer 1

# include & lt; stdio.h & gt;
int main (int argc, char * argv []) {
  int d1, d2, d3, k, n;
  printf ("Enter the number n with which we will compare the sum of the digits of the number \ n");
  scanf ("% d", & amp; n);
  k = 0;
  for (d1 = 1; d1 & lt; = 9; ++ d1)
  ...
  ...
  if (d1 + d2 + d3 == n) {
    k + = 1;
    printf ("% d% d% d", d1, d2, d3)
  }
  ...
}

What to insert instead of ellipsis, I think you’ll figure it out.