How does the TEST command work?

It is clear that this is boolean and . Flags are set. How many of them are there and by what principle are they established, if as a result of applying a logical function to two numbers, a number is obtained?

mov ax, 5878h
  mov bx, 6B36h
  mov cx, 5CFDh
P: mov al, bl
Q: test bh, cl
  jpe E
  mul ch
  shl ax, 3
  jmp F
E: imul cl
  xor cl, ah
F: sub ah, cl

Here’s another example, in it when applying the test – the result is True , how did it happen?

Answer 1, authority 100%

TEST sets the PF, SF and ZF flags.

• Parity Flag – 1 if AND results in an even number of (1) bits set.
• Sign Flag – 1 if the AND result is negative (most significant – signed – bit = 1)
• Zero Flag – 1 if the result is AND = 0

and resets CF and OF. Here’s a general outline:

Operation
TEMP ← SRC1 AND SRC2;
SF ← MSB (TEMP);
IF TEMP = 0
  THEN ZF ← 1;
  ELSE ZF ← 0;
FI:
PF ← BitwiseXNOR (TEMP [0: 7]);
CF ← 0;
OF ← 0;

The AND result itself is discarded. In your example:

6Bh AND FDh = 69h = 01101001b

PF will be set to 1. jpe will jump.