There is a specific section of the code that creates a two-dimensional field M [X] [Y] and scores it with zeros:
std :: vector & lt; std :: vector & lt; int & gt; & gt; vector_map;
vector_map.push_back (std :: vector & lt; int & gt; ());
Vector_map.Resize (Count_H);
For (unsigned int y = 0; y & lt; Count_h; y ++)
{
For (unsigned int x = 0; X & LT; Count_W; X ++)
{
vector_map [x] .push_back (0);
}
}
Count_W and Count_H initialization occurs at the moment of calling the function in which this code is contained. And …
- how to bring it all this thing? It is desirable to implement this using the same two cycles, as above.
- How to access an arbitrary field of the resulting matrix and, if necessary, change it?
I was able to make a clogging with values, as well as their conclusion:
std :: vector & lt; int & gt; vector_map;
Vector_map.Resize (Count_h * count_w);
For (unsigned int y = 0; y & lt; Count_h; y ++)
{
vector_map.push_back (y);
For (unsigned int x = 0; X & LT; Count_W; X ++)
{
vector_map.push_back (x);
}
}
For (unsigned int y = 0; y & lt; Count_h; y ++)
{
For (unsigned int x = 0; X & LT; Count_W; X ++)
{
STD :: COUT & LT; & LT; vector_map [x * y];
}
STD :: COUT & LT; & LT; STD :: ENDL;
}
The result was approximately the following:
0000000000
0000000000.
0000000000.
0000000000.
0000000000.
0000000000.
0000000000.
0000000000.
0000000000.
0000000000.
But how to access and change any arbitrary element – I can’t imagine. I hope for your help.
Thank you in advance.
Answer 1, Authority 100%
Actually, everything turned out to be much easier.
Interface:
std :: vector & lt; std :: vector & lt; int & gt; & gt; vct_map;
Implementation in Functions:
vector & lt; vector & lt; int & gt; & gt; Map (Count_W, Vector & LT; Int & GT; (Count_h)) ;;
vct_map.Resize (Count_W * Count_h);
For (int y = 0; y & lt; Count_h; y ++)
{
For (int x = 0; X & LT; Count_W; X ++)
{
Map [x] [y] = 1;
}
}
vct_map = map;
The size of the local vector in the functions are set in advance unknown values transmitted through the call to the function, processed, as I need and further is simply assigned to a class member.
It may not be an ideal solution, but very short and understandable. It completely solves my task with access to arbitrary data and reading from the result.