All the good time! This code is taken from the book Head First Java. When executed, the code is obtained in the output console as follows: “6 14”. If you take a leaf and a pen and run this code to get the answer: “6 6”. I started to understand what is the cause, and came across the fact that the for loop with a value of outer = 2; It does not start. I changed the subject to break in if at x = x-3 (ie did the same thing that did not break giving executed line x = x + 3), and got the result: “6 6”. The conclusion that due to the multiple output of the loop by the operator break, does not start the cycle. I’m sorry for the stupid question perhaps, if I may I would like to understand the reason for such behavior of the code.

Answer 1, Authority 100%

You seem to confuse them:

• break completes the cycle entirely
• continue completes the body of the loop, but continues the cycle itself

Answer 2, Authority 100%

Discard x = x + 0; it still does nothing, only making a mess in your fragile mind.
In such cases, try to look for the problem in stages, step by step.
Normal people do it with
using the debugger … give you the option of a smoker.

int x = 0;
  int y = 30;
  for (int outer = 0; outer & lt; 3; outer ++) {
    System.out.println ( "Cycle 1 runs" + outer + "/" + y);
    for (int inner = 4; inner & gt; 1; inner--) {
      System.out.println ( "Cycle 2 works" + outer + "/" + y);
      y = y - 2;
      System.out.println ( "Subtracting y =" + y);
      System.out.println ( "x == 6 -?" + (X == 6));
      if (x == 6) {
        Break;
      }
      x = x + 3;
      System.out.println ( "tripped end of the loop 2 ');
    }
    y = y - 2;
    System.out.println ( "tripped end of cycle 1");
  }
  System.out.println (x + "" + y);

– & gt; I hope this helps you to understand how to construct nested loops. Think of your tags in the output to the console that will give you a picture.