Please tell me how the program understands how min (C, D) is calculated; After all, it is not written, but only a number is written to the minimum of Min (A, B), however, the program works correctly.

Public Static Int Min (Int A, Int B, Int C, Int D) {
  if (min (a, b) & lt; min (c, d)) {
    RETURN MIN (A, B);
  } else {
    RETURN MIN (C, D);
  }
}
Public Static Int Min (Int A, Int B) {
  IF (A & LT; B)
    RETURN A;
  ELSE.
    Return B;

Answer 1, Authority 100%

are different a, b .. maybe it will be clearer?

Public Static Int Min (Int A, Int B, Int C, Int D) {
 if (MIN (A, B) & LT; MIN (C, D)) {// Call MIN (E, F) with the parameters E = A, F = B and E = C, F = D
   RETURN MIN (A, B);
 } else {
  RETURN MIN (C, D);
 }
}
Public Static Int Min (int e, int f) {
 IF (E & LT; F)
  Return E;
 ELSE.
  RETURN F;
}

There are two different functions, one with a four parameters, the other with two. That from four calls several times the one with two.

min (1,2) - & gt; 1
min (1,2,3,4) - & gt; min (1,2) & lt; min (3.4)? MIN (1,2): min (3.4) - & gt; 1