Simple number `INT `

.

It is necessary to determine whether it is divided by 10 integer.

Everything seems to be simply, but nothing in mind is coming. Help please.

## Answer 1, Authority 100%

Use for this kind of tasks The `% `

statement, which returns the left value from the division **left value **on **right **.

Example:

```
number = 10;
if (Number% 10 == 0) System.out.PrintLN ("The number is divided into 10");
```

## Answer 2, Authority 62%

For this, there is a “%” operator, the result of which is the balance of the division.

With it, this task is solved quite trivial:

```
int a = 15;
if (a% 10 == 0) // In our case, the result will be 5, then the check will not pass
{
// divided by 10 integer
...
}
ELSE.
{
// Not divisible
...
}
```

## Answer 3, Authority 50%

Here is a simple feature for checking. If it is divided – returns TRUE, otherwise – false.

```
Public Boolean Byten (int n) {
RETURN N% 10 == 0;
}
```

## Answer 4, Authority 50%

You need to use the balance of division, which means that you need

```
int number = 10;
if (Number% 10 == 0) {
System.Out.Pritln (Number);
}
```

That is, learn the match)