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Displays a two-dimensional array. Java

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created a new method, prescribed the following:

static void changediagonal () {
  System.out.PrintLN ("Task number 4");
  int [] [] listdoblediagonal = new int [10] [10];
  int i;
  For (i = 0; I & LT; ListDoubleDiagonal.Length; I ++) {
    ListDoubleDiagonal [i] [i] = 1;
    ListDoubleDiagonal [i] [listdoblediagonal.length - 1 - i] = 1;
  }
  System.Out.PrintLN (ArrayS.DeepTostring (ListDoubleDiagonal));
  System.Out.printLN ();
}

Currently, an array goes into the console, but each item does not start with a new line, but I would like. Tell me, please, some can there be a way another to output 10 lines?


Answer 1, Authority 100%

The element of the two-dimensional array is a one-dimensional array. We go around the two-dimensional array and derive its elements. This can be done in the cycle:

for (int i = 0; i & lt; listdoblediagonal.length; i ++) {
  System.Out.PrintLN (Array.Tostring (ListDoubleDiagonal [i]));
}

You can stand on the streets:

arrays.stream (ListDoubleDiagonal)
    .Foreach (ARR - & GT; System.out.PrintLN (Arrays.Tostring (Arr)));

Answer 2

Two-dimensional array output line:

int [] [] arr = new int [10] [10];
// Filling the array
Intstream.range (0, 10) .Foreach (i - & gt; {
  Arr [i] [i] = 1;
  Arr [i] [9 - i] = 1;
});
// Conclusion Building
Arrays.stream (Arr) .map (Arrays :: Tostring) .Foreach (System.out :: PrintLN);
[1, 0, 0, 0, 0, 0, 0, 0, 0, 1]
[0, 1, 0, 0, 0, 0, 0, 0, 1, 0]
[0, 0, 1, 0, 0, 0, 0, 1, 0, 0]
[0, 0, 0, 1, 0, 0, 1, 0, 0, 0]
[0, 0, 0, 0, 1, 1, 0, 0, 0, 0]
[0, 0, 0, 0, 1, 1, 0, 0, 0, 0]
[0, 0, 0, 1, 0, 0, 1, 0, 0, 0]
[0, 0, 1, 0, 0, 0, 0, 1, 0, 0]
[0, 1, 0, 0, 0, 0, 0, 0, 1, 0]
[1, 0, 0, 0, 0, 0, 0, 0, 0, 1]

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