Why with this construction of the for
cycle, it turns out endless zeros output?
int i;
for (i = 0; i & lt; 10; i = i ++) {
System.out.printLN (I);
}
Answer 1, Authority 100%
Your expression: i = i ++
. What happens here in steps:

First
i = 0
. 
The value is calculated after the sign is equal. It is zero:
result = i = 0
. 
postfix increment is calculated. Now
i = i + 1 = 1
. 
The result of expression is written in
I
. As a result:i = result = 0
.
can be replaced by: i = ++ i
. Then:

First
i = 0
. 
The prefix increment is calculated. Now
i = i + 1 = 1
. 
The value is calculated after the sign is:
result = i = 1
. 
The result of expression is written in
I
. As a result:i = result = 1
.
In general, the postfix increment in the assignment operator over the same variable does not make anything useful. From here and your infinite cycle.
Answer 2, Authority 23%
I ++ Operator
There is a brief entry i = i + 1
. But there is a version of writing ++ I
or I ++
.
The difference is when the increment operation occurs before turning to the variable or after. In your case, first the value i
is assigned to the variable i
, and then the increment occurs, but its value is not saved.
Now if you write ++ I
, then everything will work as it should work.
Answer 3, Authority 15%
It is necessary to correct in the last value of the cycle parameters on:
for (int i = 0; i & lt; 10; i ++) {
System.out.printLN (I);
}
In your case, after each iteration of the cycle, you are assigned i = 0 (as ++ happens after the assignment), and the cycle again processes i = 0