Write a program that reads the number of integers n, and then reads the numbers separated by a space, and writes to the array, but something does not work

import java.util.Scanner;
class Class {
public static void main (String [] args) {
  Scanner n = new Scanner (System.in);
  Scanner scan = new Scanner (System.in);
  int k [] = new int [n];
    k = scan.nextInt ();
    System.out.println ( "Filling an array");
    System.out.print (k + "");
  }
}

Answer 1, Authority 100%

You do not have a cycle in which the numbers are written to the array, and you have not displayed.
If you have a certain number of elements, then the code would be more correct to look something like this:

import java.util.Scanner;
class Class {
public static void main (String [] args) {
  Scanner scan = new Scanner (System.in);
  int k [] = new int [10];
  for (int i = 0; i & lt; k.length; i ++) {// search of all elements
      k [i] = scan.nextInt ();
    }
    System.out.println ( "Filled with an array");
    for (int i = 0; i & lt; k.length; i ++) {// search of all elements
      System.out.print (k [i] + "");
    }
  }
}

That is, if I have correctly understood the essence of your question.

Clarification by the condition:

import java.util.Scanner;
class Class {
public static void main (String [] args) {
  System.out.println ( "Number of elements in the array:");
  Scanner n = new Scanner (System.in);
  int num = n.nextInt ();
  System.out.println ( "Array elements");
  Scanner scan = new Scanner (System.in);
  int k [] = new int [num];
  for (int i = 0; i & lt; k.length; i ++) {
    k [i] = scan.nextInt ();
    }
    System.out.println ( "Filled with an array");
    for (int i = 0; i & lt; k.length; i ++) {
    System.out.print (k [i] + "");
    }
  }
}