Help me understand how forEach works in js. There was a good illustrative example. One and the same problem solved using “for” and “forEach”
Thanks

I’ll format my question to make it clearer. Thanks for the answer to those who answered.
Because of what the question arose. I figured out how to rewrite this code using forEach

let length = 1;
  snake = [];
  for (let i = length - 1; i & gt; = 0; i--) {
  }

And it turned out to be not as easy as I thought. That is why I need a visual example with forEach and for to understand how it works. I would be grateful

Answer 1, authority 100%

The forEach () method executes the specified function once for each element in the array.

arr.forEach (callback [ thisArg])

callback -

The function that creates an element of the new array takes three arguments:

currentValue

The current element being processed in the array.

index

The index of the currently processed element in the array.

array

The array to traverse.

thisArg

Optional parameter. The value to use as this when calling the callback function.

The forEach () method executes the callback function once for each element in the array in ascending order. It will not be called for deleted or missing array elements. However, it will be called for elements that are present in the array and have the value undefined .

The callback function will be called with three arguments:

element value (value )
element index (index )
array to traverse (array )
If the thisArg parameter was passed to the forEach () method, it will be used as the this value when the callback is called. Otherwise, undefined will be used as the this value. Ultimately, the this value seen from the callback function is determined according to the usual rules for defining this as seen from the function.

The range of elements processed by the forEach () method is set before the first call to the callback function. Items added to the array after the forEach () method starts executing will not be visited by the callback function. If the existing array elements change, the values ​​passed to the callback function will be the values ​​at the time the forEach () method visits them; deleted items will not be visited.

function logArrayElements (element, index, array) {
 console.log ('a [' + index + '] =' + element);
}
// Note the skip at index 2, there is no element, so it is not visited
[2, 5, 9] .forEach (logArrayElements);
// logs:
// a [0] = 2
// a [1] = 5
// a [3] = 9 

var a = ["a", "b", "c"];
a.forEach (function (entry) {
  console.log (entry);
});