Just learning, here’s my sketch. What’s missing?

var num = 2;
var exp = 10;
var count = 2;
var result = num;
for (var count = 2; count & lt; = exp; count ++) {
  console.log (count);
}

The number 1024 should be displayed in the console.

Answer 1, authority 100%

Let’s first describe the algorithm. “2 to the power of 10” means that you need to multiply 10 twos. 2 * 2 * 2 ... * 2 – & nbsp; two ten times, multiplication 9 times.

In order not to write a long sausage of multiplications, let’s do it in a loop, as requested.

Let there be a result variable that stores the current value of the multiplication. And inside the loop, which we will loop 9 times (how many times “multiplication”), we will multiply by 2:

for (blabblah) {
  result = result * 2;
}

This result will contain the desired result after nine times.

It remains to arrange the cycle. Inside there are three expressions:

1. Initial values.
2. Conditions to be met. As soon as they are violated – & nbsp; exit the loop.
3. Actions on every repeat.

Let’s do the counter i with the variable. Repeat 9 times, each time decreasing by 1. Spin until we reach zero:

for (i = 9; i & gt; 0; i = i-1)

And finally, at the very beginning, you need to declare / give initial values ​​to all variables:

var i, result, exp = 10, num = 2;

Next, please collect it yourself. Almost everything is here. Instead of a fixed value, use the exp variable in the loop.

Answer 2, authority 40%

function power (base, exp) {
  var result = 1;
  for (var i = 0; i & lt; exp; i ++)
  {
    result = result * base;
  }
  return (result);
}
console.log (power (2,10));

Answer 3

var num = 2;
var exp = 10;
var result = 1;
var cnt = 1;
while (cnt & lt; = exp) {
 result = result * num;
 console.log (result)
 cnt ++;
}

Answer 4

function power (base, exponent) {
if (exponent == 0) {
return 1;
} else {
return base * power (base, exponent - 1)
}
}
console.log (power (2,10);