I want these items to have and brought 13250 (10000 + 2000 + 1250 ).

Answer 1, Authority 100%

the shortest way

print (SUM (LIS))

Answer 2, Authority 43%

That’s how:

import Functools, Operator
LIS = [10000, 2000, 1250]
Print (Operator.add, Lis))

Answer 3, Authority 29%

lis = [10000, 2000, 1250]
Sum = 0.
For i in lis:
  SUM + = I
Print (SUM)

So you can practice in iterative objects

Answer 4, Authority 14%

And so you can practice the Range method:

lis = [10000, 2000, 1250]
Sum = 0.
For i in Range (LEN): # Argument: Stop
  SUM + = LIS [i]
Print (SUM)

So from the end:

lis = [10000, 2000, 1250]
Sum = 0.
For i in Range (LEN (LIS) -1, -1, -1): # Arguments: Start, Stop, Step
  SUM + = LIS [i]
Print (SUM)

Answer 5

• lis = [10000, 2000, 1250]
  Print (SUM (LIS))
  

• lis = [10000, 2000, 1250]
  Sum = 0.
  For i in lis:
    SUM + = I
    Print (SUM)