tell me how you can accept the entered user text

import telebot
bot = telebot.TeleBot ('token')
keyboard = telebot.types.ReplyKeyboardMarkup (True, True)
keyboard1 = telebot.types.ReplyKeyboardMarkup (True)
keyboard.row ('SMS', 'Calls')
keyboard1.row ('Back')
phone = ''
@ bot.message_handler (commands = ['start'])
def start_messages (message):
  bot.send_message (message.from_user.id, "What type of message would you like to make?", reply_markup = keyboard)
@ bot.message_handler (content_types = ['text'])
def after_text (message):
  if message.text == 'SMS':
    input1 = message.text
    bot.send_message (message.from_user.id, 'Enter phone number:', reply_markup = keyboard1)
    bot.register_next_step_handler (message, after_text)
  elif message.text == 'Calls':
    bot.send_message (message.from_user.id, 'Coming soon ...', reply_markup = keyboard1)
  elif message.text == 'Back':
    bot.send_message (message.from_user.id, 'What type of message would you like to make?', reply_markup = keyboard)
  else:
    bot.send_message (message.from_user.id, 'I don't understand you')
bot.polling (none_stop = True, interval = 0)

I saw on the Internet they write that you need to use bot.register_next_step_handler (message, after_text) What’s next, how to make the phone variable take the value of the entered person’s number?

Answer 1, authority 100%

@ bot.message_handler (content_types = ['text'])
def after_text (message):
  if message.text == 'SMS':
    msg = bot.send_message (message.from_user.id, 'Enter phone number:', reply_markup = keyboard1)
    bot.register_next_step_handler (msg, after_text_2)
...
def after_text_2 (message):
  print ('the phone number entered by the user at the "sms" step:', message.text)

bot.register_next_step_handler takes two arguments:

• to whom \ where / what to send
• which step (function) to go to

after sending msg , waiting for input is performed, followed by “forwarding” to the function specified by the second argument.

this is if on your fingers.