Prompt. when I write this code
a = int (input ()) b = int (input ()) c = int (input ()) p = (a + b + c) / 2 S = p (p - a) (p - b) (p - c) math.sqrt (S) print (S)
throws TypeError: ‘float’ object is not callable
This is probably something simple, but I just can’t figure it out. Thanks in advance
Answer 1, authority 100%
S = p (p - a) (p - b) (p - c)
p contains a real value (
p (p - a) syntax for calling an object as a function.
I think the correct code would be:
S = p * (p - a) * (p - b) * (p - c)
Answer 2, authority 20%
p (...)– call object p as a function with an argument from parentheses
p * (...)– multiply p by the result of the expression in parentheses.
a = int (input ()) b = int (input ()) c = int (input ()) p = (a + b + c) / 2 S = (p * (p - a) * (p - b) * (p - c)) ** 0.5 # need to put multiplication signs # root can be calculated as a number to the 1/2 power i.e. ** 0.5 print (S)